Using de Broglie's equation, λ = h/mv which would have a larger wavelength, a slow-moving proton or a fast-moving golf ball? Explain your answer.

Answer : The correct option is a slow-moving proton.

Explanation :

The de Broglie's equation is,

[tex]\lambda =\frac{h}{mv}[/tex]

where,

[tex]\lambda[/tex] = wavelength of particle

h = Planck's constant

m = Mass of particle

v = speed of particle

From the de Broglie's equation, we conclude that there is an inverse relationship between the wavelength and speed or mass of particle. That means the lower the speed and mass of particle, higher will be the wavelength of particle and vice-versa.

So, a slow-moving proton have a larger wavelength due to slow speed of proton.