Question
Find the equation of a line with the given points. (Put your answers in the form y = mx + b.) (2, 2) (3, 3)
Asked by: USER8114
108 Viewed
108 Answers
Answer (108)
y= 1x
i think the y-intercept is 0 but idk
i think the y-intercept is 0 but idk
Well, Here is how you do it!
Find the slope:
[tex] \frac{3-2}{3-2} = \frac{1}{1} = 1[/tex]
So the equation would look like this so far:
y = x + b
Now find the y-Intercept using a little common sense :)
(if x = 2 and y = 2, if x = 0 then y = 0)
b = 0
And the Equation looks like this:
y = x
Hope this helps!
Find the slope:
[tex] \frac{3-2}{3-2} = \frac{1}{1} = 1[/tex]
So the equation would look like this so far:
y = x + b
Now find the y-Intercept using a little common sense :)
(if x = 2 and y = 2, if x = 0 then y = 0)
b = 0
And the Equation looks like this:
y = x
Hope this helps!