Question
On the plane curve defined by the parametric equations below, what point corresponds to t= -1
x=2t-1
y=t^3
(2,1)
(1,2)
(-1,3)
(-3,-1)
x=2t-1
y=t^3
(2,1)
(1,2)
(-1,3)
(-3,-1)
Asked by: USER4125
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175 Answers
Answer (175)
The equation x=2t-1 represent the x-coordinate. To get the value of x, substitute t with -1.
That is: x = 2(-1) - 1
= -2-1
= -3
Likewise, the equation y=t∧-3 represent the y-coordinate. Substituting t with -1,
y = (-1)∧-3
= -1
The point that correspond to t=-1 is (-3,-1).
That is: x = 2(-1) - 1
= -2-1
= -3
Likewise, the equation y=t∧-3 represent the y-coordinate. Substituting t with -1,
y = (-1)∧-3
= -1
The point that correspond to t=-1 is (-3,-1).
Answer: I just took the test and got 100%
1. C, the parameter is t and the curve contains the set of points (2cos(t), sin(t)
2. B, up to the left and then up to the right
3. D, (-3,-1)
Feel free to mark as brainliest (: