Question
in an isosceles right triangle the hypotenuse is 8.4 in find the length of a side to the nearest tenth of an inch
Asked by: USER2868
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Answer (113)
a2+a2=8.42
2a2=8.42
a2=(8.4)22
a2=70.562
a2=35.28
a≈5.9
In an isosceles right triangle, the two legs will be equal to each other. We can use the Pythagorean Theorem as follows:
a² + a² = 8.4² where 'a' is the length of the two equal legs
2a² = 70.56
[tex] a^{2} = \frac{70.56}{2} [/tex]
[tex]a= \sqrt{ \frac{70.56}{2} } [/tex]
a = 5.9 to the nearest tenth of an inch.
a² + a² = 8.4² where 'a' is the length of the two equal legs
2a² = 70.56
[tex] a^{2} = \frac{70.56}{2} [/tex]
[tex]a= \sqrt{ \frac{70.56}{2} } [/tex]
a = 5.9 to the nearest tenth of an inch.