Question
Find the difference.
(9x2 + 10x + 4) − (9x2 + 5x − 1)
(a) 5x + 5
(b) 15x + 3
(c) x2 + 5x + 5
(d) x2 + 15x + 3
(9x2 + 10x + 4) − (9x2 + 5x − 1)
(a) 5x + 5
(b) 15x + 3
(c) x2 + 5x + 5
(d) x2 + 15x + 3
Asked by: USER9536
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151 Answers
Answer (151)
[9x2+10x+4]-[9x2+5x-1]
9x2-9x2 gone
10x-5x=5x
4-[-1]=5
ans=5x+5 opt a
9x2-9x2 gone
10x-5x=5x
4-[-1]=5
ans=5x+5 opt a
For this case we have the following polynomials:
[tex](9x ^ 2 + 10x + 4) (9x ^ 2 + 5x - 1) [/tex]
Subtracting both polynomials we have:
[tex](9x ^ 2 + 10x + 4) - (9x ^ 2 + 5x - 1) [/tex]
We group terms with the same exponent:
[tex](9x ^ 2 - 9x ^ 2) + (10x - 5x) + (4 - (-1)) [/tex]
Rewriting we have:
[tex](9x ^ 2 - 9x ^ 2) + (10x - 5x) + (4 +1) 5x + 5[/tex]
Answer:
The difference is given by:
(a) 5x + 5
[tex](9x ^ 2 + 10x + 4) (9x ^ 2 + 5x - 1) [/tex]
Subtracting both polynomials we have:
[tex](9x ^ 2 + 10x + 4) - (9x ^ 2 + 5x - 1) [/tex]
We group terms with the same exponent:
[tex](9x ^ 2 - 9x ^ 2) + (10x - 5x) + (4 - (-1)) [/tex]
Rewriting we have:
[tex](9x ^ 2 - 9x ^ 2) + (10x - 5x) + (4 +1) 5x + 5[/tex]
Answer:
The difference is given by:
(a) 5x + 5