Question
A discount book store sells hardcover books for $8 each and paperbacks for $4 each.The number of hardcover books, h, sold one day was 2 more than four times the number of paperback books, p, sold that same day. The total amount of sales for that day was $160. Jean-Paul wrote the following system of linear equations to find the number of each type of book sold.
8h+4p=160
p=4h+2
What is Jean-Paul’s error?
A. Jean-Paul should have written the first equation as h+p=160
B. Jean-Paul should have written the first equation as 4h+8p=160
C. Jean-Paul should have written the second equation as h=4p+2
D. Jean-Paul should have written the second equation as p+2=4h
8h+4p=160
p=4h+2
What is Jean-Paul’s error?
A. Jean-Paul should have written the first equation as h+p=160
B. Jean-Paul should have written the first equation as 4h+8p=160
C. Jean-Paul should have written the second equation as h=4p+2
D. Jean-Paul should have written the second equation as p+2=4h
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Answer:
C. Jean-Paul should have written the second equation as h=4p+2
Step-by-step explanation:
Let the hardcover books be denoted by = h
Let the paperback books be denoted by = p
A discount book store sells hardcover books for $8 (8h) each and paperbacks for $4 each (4p).
The total amount of sales for that day was $160. Equation forms:
[tex]8h+4p=160[/tex]
The number of hardcover books, h, sold one day was 2 more than four times the number of paperback books, p, sold that same day. Equation forms:
[tex]h=4p+2[/tex]
Now we can see that Jean Paul made a mistake writhing this second equation. She interchanged 'p' and 'h'.
So, the correct answer is option C.