Question
What's the probability a dealer deals himself an ace on the first deal?
Asked by: USER1795
71 Viewed
71 Answers
Answer (71)
There are 52 cards in a deck. There are four aces.
Therefore,
Probability of dealing an ace = P(A)
[tex]P(A) = \frac{4}{52} = 0.07692307692 = 7.692307692 \%[/tex]
Therefore,
Probability of dealing an ace = P(A)
[tex]P(A) = \frac{4}{52} = 0.07692307692 = 7.692307692 \%[/tex]