what is the value of r in this equation? 4(x-3)-r+2x=5(3x-7)-9x

4(x-3)-2+2x=5(3x-7)-9x

4x-12-r+2x=5(3x-7)-9

4x-12-r+2x=15x-35-9x

6x-12-r=15x-35-9x

6x-12-r=6x-35

add 12 to -35 which equals -23.

add 6x+6x it cancels out to 0.

-r=-23

to make r positive just add it -23

since 23 is already negative it would become a positive because a negative + negative= positive

answer: r=23