Question
Consider the curve y = x − x^3, find the slope of the tangent line to the curve at the point (1, 0).
Asked by: USER8136
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Answer (100)
The derivative of a function, such as the one given above, represents the slope of the tangent line to the curve at the given point.
In this case, y = x − x^3, and dy/dx = 1 - 3x^2. Letting x = 1, we get the slope of the tangent line at the point (1,0): 1 - 3(1^2) = -2 (answer)