Question
exercice : calculer les expression suivante en ecrivant les etapes intermediaires :
a=2-3+8-11 b= -5+9-6 c= 103.3-9+3.3 d=-9+(-9)+3(-2) e=-7-5-3
Asked by: USER2222
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Answer (232)
a=2-3+8-11
a = 5+ 8 - 11
a = 13-11
a= 2
b= -5+9-6
b= 14-6
b= 8
c= 103.3-9+3.3
c= 94,3 + 3,3
c = 97,6
d=-9+(-9)+3(-2)
d= 0 + (-6)
d = -6
e=-7-5-3
e= -12 - 3
e= -15