Question
salut
simplifié la fraction rationnelle A,B ,C
A= 4x²-10x+25 / 2X²-5X
B= 144x-4x3 / X3+12X²+36
c= 2 / 4X²-49
MERCI DE M AIDER
Asked by: USER7838
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244 Answers
Answer (244)
A= 4x²-10x+25 / 2X²-5X
=(2x-5)²/((2x-5)x)
=(2x-5)/x
=2-5/x
B= 144x-4x3 / X3+12X²+36 x
=(4x)(6-x)(6+x)/(x(x+6)²)
=4(6-x)/(6+x)
c= 2 / 4X²-49
=2/((2x-7)(2x+7))
=(2x-5)²/((2x-5)x)
=(2x-5)/x
=2-5/x
B= 144x-4x3 / X3+12X²+36 x
=(4x)(6-x)(6+x)/(x(x+6)²)
=4(6-x)/(6+x)
c= 2 / 4X²-49
=2/((2x-7)(2x+7))
Bonjour,
[tex]A= \dfrac{4x^2-10x+25}{2x^2-5x}\\\\A= \dfrac{(2x-5)^2}{x(2x-5)}\\\\A= \dfrac{(2x-5)(2x-5)}{x(2x-5)}\\\\A= \dfrac{2x-5}{x}[/tex]
[tex]B=\dfrac{144x-4x^3}{x^3+12x^2+36x}\\\\B=\dfrac{x(144-4x^2)}{x(x^2+12x+36)}\\\\B=\dfrac{4x(36-x^2)}{x(x+6)^2}\\\\B=\dfrac{4x(6-x)(6+x)}{x(x+6)(x+6)}\\\\B=\dfrac{4x(6-x)(6+x)}{x(x+6)(6+x)}\\\\B=\dfrac{4(6-x)}{x+6}[/tex]
[tex]C=\dfrac{2}{4x^2-49}\\\\C=\dfrac{2}{(2x)^2-7^2}\\\\C=\dfrac{2}{(2x-7)(2x+7)}[/tex]
[tex]A= \dfrac{4x^2-10x+25}{2x^2-5x}\\\\A= \dfrac{(2x-5)^2}{x(2x-5)}\\\\A= \dfrac{(2x-5)(2x-5)}{x(2x-5)}\\\\A= \dfrac{2x-5}{x}[/tex]
[tex]B=\dfrac{144x-4x^3}{x^3+12x^2+36x}\\\\B=\dfrac{x(144-4x^2)}{x(x^2+12x+36)}\\\\B=\dfrac{4x(36-x^2)}{x(x+6)^2}\\\\B=\dfrac{4x(6-x)(6+x)}{x(x+6)(x+6)}\\\\B=\dfrac{4x(6-x)(6+x)}{x(x+6)(6+x)}\\\\B=\dfrac{4(6-x)}{x+6}[/tex]
[tex]C=\dfrac{2}{4x^2-49}\\\\C=\dfrac{2}{(2x)^2-7^2}\\\\C=\dfrac{2}{(2x-7)(2x+7)}[/tex]