Question
Bonjour comment on factorise et developpe cette expression: (3-x)au carré - 16 ?
Asked by: USER4162
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81 Answers
Answer (81)
factoriser :
(3-x)² - 16 = (3-x)² - 4² = (3-x-4)(3-x+4) = (-1-x)(7-x)
développer :
(3-x)² - 16 = 9 - 6x + x² - 16 = x² - 6x - 7
(3-x)² - 16 = (3-x)² - 4² = (3-x-4)(3-x+4) = (-1-x)(7-x)
développer :
(3-x)² - 16 = 9 - 6x + x² - 16 = x² - 6x - 7
Factorisation :
(3 - x)² - 16
= (3 - x)² - 4²
= (3 - x + 4)(3 - x - 4)
= (7 - x)(- x - 1)
Développement :
(3 - x)² - 16
= 9 - 6x + x² - 16
= x² - 6x - 7
(3 - x)² - 16
= (3 - x)² - 4²
= (3 - x + 4)(3 - x - 4)
= (7 - x)(- x - 1)
Développement :
(3 - x)² - 16
= 9 - 6x + x² - 16
= x² - 6x - 7