Urgent resoudre un systeme d equation avec methode de substitution
2x+3y=56
3x+2y=54
Merci de M aide ......

By: USER3771
27 Agustus 2025 mathematiques 5 minutes
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Grade: Education Subject: mathematiques
Urgent resoudre un systeme d equation avec methode de substitution
2x+3y=56
3x+2y=54
Merci de M aide ......
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{2x+3y=56 => 2x=56-3y   => x=(56-3y)/2

{3x+2y=54 

  [tex]3* \frac{56-3y}{2} +^{2/}2y=^{2/}54 => \\ 168-9y+4y=108 \\ -5y=-60 \\ y=12[/tex]

x=(56-12*3)/2=(56-36)/2=20/2=10

x=10

y=12

Answered on 27 Agustus 2025
(63)
c'est les deux calcules faut faire s'il te plait ??

Answered on 27 Agustus 2025

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