Développer et réduire(4x+3)(-2x-5)et -x(8x-3)

By: USER3485
27 Agustus 2025 mathematiques 5 minutes
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46 views 46 comments 13 shares
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Question

Grade: Education Subject: mathematiques
Développer et réduire(4x+3)(-2x-5)et -x(8x-3)
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Best Answer
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Réponse :

Explications étape par étape :

Bonjour

(4x+3)(-2x-5)
=-8x² - 20x - 6x - 15
= -8x² - 26x - 15

-x(8x-3)
= -8x² + 3x

Answered on 27 Agustus 2025
(229)

bonjour;

(4x+3)(-2x-5)

= -8x² -20x -6x -15

= -8x² -26x -15

et

-x(8x-3)

= -8x² +3x

Answered on 27 Agustus 2025

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