Un volum de 1L CH4 se clorureaza cu 1.4L Cl2. Stiind ca din proces rezultă numai CH3Cl si CH2Cl2, iar reactantii se consuma integral, care este raportul între clorura de metil si clorura de metilen?

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Clasă: Education Materie: chimie

Întrebare a fost pusă de: USER2552

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USER5363

Cel mai bun răspuns

(552)

Răspuns:

Explicație:

niu,CH4=V/Vm= 1/22,4mol=0,0446 mol

niu,Cl2= 1,4/22,4mol= 0,0625mol

CH4 + Cl2------> CH3Cl+HCl ori a,mol

CH4+2Cl2---> CH2Cl2+2HCl ori b,mol

mol CH4: a + b= 0,0446

molCl2: a+2b= 0,0625

rezulta: a=0,0267mol b= 0,0179mol

niu,CH3Cl/ niu,CH2Cl2= a/b= 0,0267/0,0179 aproximativ 1,49

Răspunsul a fost dat în data 2 September 2025

Un volum de 1L CH4 se clorureaza cu 1.4L Cl2. Stiind ca din proces rezultă numai CH3Cl si CH2Cl2, iar reactantii se consuma integral, care este raportul între clorura de metil si clorura de metilen?

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